x^2+3x=104

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Solution for x^2+3x=104 equation:



x^2+3x=104
We move all terms to the left:
x^2+3x-(104)=0
a = 1; b = 3; c = -104;
Δ = b2-4ac
Δ = 32-4·1·(-104)
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5\sqrt{17}}{2*1}=\frac{-3-5\sqrt{17}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5\sqrt{17}}{2*1}=\frac{-3+5\sqrt{17}}{2} $

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